If you have this
for($i = 0; $i < 10; $i++) include(\'whatever.php\');
Will it pull the file ten actual times, or will it only access th
If you're asking if the file is going to be cashed and included from memory instead of parsed and compiled to PHP bytecode again and again: -Yes, you will process the same file n times if you include that given file n times. This is the standard PHP behavior but...
You can change that (and it seems to me that you're looking for that?). As I said, PHP will include the file the first time and will not cache it for you... unless you're using any PHP caching module like APC:
When using APC, things are going to be different, the outputted result will be the same but the server behavior will change a lot! The first time you include a file it will be parsed, compiled into PHP bytecode (machine readable instructions) and will get stored in a shared memory. Later, unless that given file gets modified, it will NOT be processed again! PHP will go straight to the pre-compiled version of your program and execute it, saving you a lot of time and resources! Good for high traffic web applications.
More about APC here
Simple enough to check - put a sleep() in there, have the file do some output, and during one of the sleep periods, modify the file to change its output.
whatever.php:
<?php
echo 'hello from version 1.0';
sleep(10);
then during one of the sleeps, change it to "version 2.0" using another shell. If the output doesn't change, then PHP has loaded the file ONCE and cached it - you'll still get 10 copies of the file's output/effects, but you'll know that PHP didn't hit the disk 10 times.
It will include the file ten times.
If that's a problem, you could use include_once