Extract files in a zip to root of a folder?

Question

I have a zip file uploaded to server for automated extract.

the zip file construction is like this:

/zip_file.zip/folder1/image1.jpg
/zip_file.zip/fo         


        

Answer 1

Use this little code snippet instead. It removes the folder structure in front of the filename for each file so that the whole content of the archive is basically extracted to one folder.

<?php
$path = "zip_file.zip";

$zip = new ZipArchive();
if ($zip->open($path) === true) {
    for($i = 0; $i < $zip->numFiles; $i++) {
        $filename = $zip->getNameIndex($i);
        $fileinfo = pathinfo($filename);
        copy("zip://".$path."#".$filename, "/myDestFolder/".$fileinfo['basename']);
    }                  
    $zip->close();                  
}
?>

Answer 2

You can do so by using the zip:// syntax instead of Zip::extractTo as described in the php manual on extractTo().

You have to match the image file name and then copy it:

if ($entry['size'] > 0 && preg_match('#\.(jpg)$#i', $entry['name'])) {
  copy('zip://' . $file_path . '#' . $entry['name'], '/root_dir/' . md5($entry['name']) . '.jpg');
}

The above replaces your for loop's if statement and makes your extractTo unnecessary. I used the md5 hash of the original filename to make a unique name. It is extremely unlikely you will have any issues with overwriting files, since hash collisions are rare. Note that this is a bit heavy duty, and instead you could do str_replace('/.', '', $entry['name']) to make a new, unique filename.

Full solution (modified version of your code):

<?php
$zip = new ZipArchive();
if ($zip->open($file_path)) {
  for ($i = 0; $i < $zip->numFiles; $i++) {
    $entry = $zip->statIndex($i);
    // is it an image?
    if ($entry['size'] > 0 && preg_match('#\.(jpg)$#i', $entry['name'])) {
      # use hash (more expensive, but can be useful depending on what you're doing
      $new_filename = md5($entry['name']) . '.jpg';
      # or str_replace for cheaper, potentially longer name:
      # $new_filename = str_replace('/.', '', $entry['name']);
      copy('zip://' . $file_path . '#' . $entry['name'], '/myFolder/' . $new_filename);
    }
  }
  $zip->close();
}
?>

Answer 3

Here: (i tried to manage everything)

$zip = new ZipArchive();
if( $zip->open($file_path) ){
    $files = array();
    for( $i = 0; $i < $zip->numFiles; $i++){
        $entry = $zip->statIndex($i);
        // is it an image?  
        if( $entry['size'] > 0 && preg_match('#\.(jpg)$#i', $entry['name'] ) ){
            $f_extract = $zip->getNameIndex($i);
            $files[] = $f_extract; /* you man want to keep this array (use it to show result or something else) */

            if ($zip->extractTo($dir_name, $f_extract) === TRUE) {
                $solid_name = basename($f_extract);
                if(strpos($f_extract, "/")) // make sure zipped file is in a directory
                {
                    if($dir_name{strlen($dir_name)-1} == "/") $dir_name = substr($dir_name, 0, strlen($dir_name)-1); // to prevent error if $dir_name have slash in end of it
                    if(!file_exists($dir_name."/".$solid_name)) // you said you don't want to replace existed file
                        copy($dir_name."/".$f_extract, $dir_name."/".$solid_name); // taking file back to where you need [$dir_name]
                    unlink($dir_name."/".$f_extract); // [removing old file]
                    rmdir(str_replace($solid_name, "", $dir_name."/".$f_extract)); // [removing directory of it]
                }
            } else {
                 echo("error on export<br />\n");
            }
        }
    }


    $zip->close();
}