using preceding-sibling with with xsl:sort

Question

I\'m trying to use preceding-sibling and following-sibling with a subset of records with a sort on them. The problem that the preceding / following brings back values from t

Answer 1

Although XSLT/XPath often talks of a "sequence of nodes", it's actually more accurate to think of it as a "sequence of node references" - because, for example, the same node can appear more than once in the sequence. When you sort a sequence of node references, you don't change the individual nodes in any way, you only change the sequence. That means the nodes still exist in their original tree exactly where they were before, and their parents, siblings, and descendants are exactly as they were before.

What you want is not the preceding and following siblings of the node, but the nodes that come before and after it in the sorted sequence, which is a quite different thing.

One way to do this is to construct a new tree containing copies of the original nodes, which you get, for example, if you do

<xsl:variable name="x">
  <xsl:for-each ...>
    <xsl:sort ...>
      <xsl:copy-of select="."/>

The sibling relationships of the copied nodes will then reflect the sorted order. There's the minor problem that in XSLT 1.0, $x is a result tree fragment so you have to convert it to a node-set using the exslt:node-set() function.

In fact in XSLT 1.0 that's probably the only way of doing it, because the XSLT 1.0 data model only has node sets, not sequences, which means there is no way of capturing and processing a sequence of nodes in anything other than document order. The 2.0 model has much more flexibility and power. Upgrade if you can - XSLT 1.0 is approaching 20 years old.

Answer 2

The preceding-sibling axis gets the preceding siblings of the context node in document order.

To refer to the preceding siblings of a node after sorting, you will need to store the sorted nodes in a variable first - and, in XSLT 1.0, convert the variable into a node-set.

Answer 3

Thanks to Michael for the answer. Posted here for completeness. Complicated because of the name spaces in use in the xml:

  <!-- Puts the whole of the Salary Node into a variable-->
  <xsl:variable name="SALARY" >
    <xsl:copy-of select="p:Salaries" />
  </xsl:variable>

  <!-- Puts the the required key data into a node-set with the correct sort applied-->
  <xsl:variable name="SAL">
    <xsl:for-each select="msxsl:node-set($SALARY)//p:Salary">
      <xsl:sort select="number(cs:Convertdatetolong(cs:AddOffsetMinutes(substring(p:CreatedDate/d5p1:DateTime,1,19),p:CreatedDate/d5p1:OffsetMinutes)))" order="ascending"/>
      <xsl:copy-of select="." />
    </xsl:for-each>
  </xsl:variable>

<!-- Quick Output-->
  <xsl:for-each select="msxsl:node-set($SAL)//p:Salary">
    <xsl:text>Sa:</xsl:text>
    <xsl:value-of select="position()" />
    <xsl:text>Preceding:</xsl:text>
    <xsl:value-of select="preceding-sibling::p:Salary[1]/p:Base"/>
    <xsl:value-of select="$newline" />
    <xsl:text>Current:</xsl:text>
    <xsl:value-of select="p:Base"/>
    <xsl:value-of select="$newline" />
    <xsl:text>Following:</xsl:text>
    <xsl:value-of select="following-sibling::p:Salary[1]/p:Base"/>
    <xsl:value-of select="$newline"/>
  </xsl:for-each>