matching parentheses in python regular expression

Question

I have something like

store(s)

ending line like 1 store(s) .. I want to match , it using python regular expression.

I

Answer 1

In more or less direct reply to your comment

Try this

import re
s = '1 stores(s)'
if re.match('store\(s\)$',s):
    print('match')

The solution is to use re.search instead of re.match as the latter tries to match the whole string with the regexp while the former just tries to find a substring inside of the string that does match the expression.

Answer 2

have you considered re.match('(.*)store\(s\)$',text) ?

Answer 3

Python offers two different primitive operations based on regular expressions: match checks for a match only at the beginning of the string, while search checks for a match anywhere in the string (this is what Perl does by default)

Straight from the docs, but it does come up alot.