Compile error when providing interface as an arraylist type

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一向
一向 2020-12-21 07:14

I have an interface defined as

interface ListItem {
    public String toString();
    public String getUUID();
}

And a class (Browse

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3条回答
  • 2020-12-21 07:44

    ArrayList<listItem> is not equal to ArrayList<browseItem>

    They are strictly type safe

    you can make use of ?

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  • 2020-12-21 07:45

    your example doesnt work, but you can use

    ArrayList<? extends ListItem> list = (method returning ArrayList of type browseItem)
    

    this should work.

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  • 2020-12-21 07:54

    Java generics are not covariant.

    See (among many other questions on SO):

    • java generics covariance
    • Java covariance
    • Java collections covariance problem
    • Using generic collections in arguments

    Solutions:

    • Change the return type of the problematic method. That is, change

      List<listItem> = (method returning List of type browseItem)
      // to
      List<listItem> = (method returning List of type listItem)
      
    • Use wildcard covariance (I think that's what this is called):

      List<? extends listItem> = (method returning List of type browseItem)
      

      Be aware that you cannot add items to the list if you take this route.


    N.B. it is generally good practice to declare list types as List<T> and not ArrayList<T>. The pseudocode above reflects this.

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