C Code for String matching[Head First C] doesn't seem to work

Question

#include 
#include 

char tracks[][80] = {
\"I left my heart in Harvard Med School\",
\"Newark, Newark - a wonderful town\",
\"Dancing         


        

Answer 1

As already pointed out by @cnicutar, fgets leaves the newline char (code 10) in the string. You can find this out by yourself by iterating over the char array and printing the character codes and looking the special chars up in an ASCII code table (http://www.asciitable.com/):

int main()
{
    int i;
    char search_for[80];
    printf("Search for: ");
    fgets(search_for, 80, stdin);
    scanf("%79s", search_for);

    // print index, char code, char itself
    for (i=0;i<80;i++) {
        printf("%d: %d %c\n", i, search_for[i], search_for[i]);
    }
    find_track(search_for);
    getch();

    return 0;
}

The output will be:

...
0: 116 t
1: 111 o
2: 119 w
3: 110 n
4: 10
5: 0 
...

You can use the function "scanf" and limit the number of read chars to 79 (1 char reserve for NULL char at the end of the string as the buffer holds max 80 chars). See: http://www.cplusplus.com/reference/clibrary/cstdio/scanf/ for reference.

int main()
{
    char search_for[80];

    printf("Search for: ");
    scanf("%79s", search_for);

    find_track(search_for);

    return 0;
}

Answer 2

The problem with the code above is that it doesn't account for the fact that fgets leaves the newline in the string. So when you type town and hit enter, you'll end up searching for "town\n".

A cheap way to solve this would be to fix the string after calling fgets

search_for[strlen(search_for) - 1] = 0;