How to unwrap a &Result<_,_>?

Question

What is a good way to extract data from a &Result type?

In my specific case, I have a &Result type, which I

Answer 1

You are looking for Result::as_ref:

Converts from Result<T, E> to Result<&T, &E>.

Produces a new Result, containing a reference into the original, leaving the original in place.

The following code solves your problem:

let entry: &DirEntry = result.as_ref().unwrap();

For a mutable version, Result::as_mut is provided.