How do I select every pair of 2 sequential elements in jQuery?

Question

Can anyone please help me to work out how to achieve the following? I have a set of divs of unknown size. Each div has a class of .feature. I need to run a jQuery script to

Answer 1

idea

$('div.feature:even').each(function(){
  var t = $(this);
  var paired = t.add( $('div.feature:eq('+(t.index()+1)+')', t.parent()) );
  //add to array, call function...
}

May need little tweaking in order to work for you - it's untested.

preview

http://jsbin.com/okize/7

Answer 2

This is my solution that I used for a elements of a blog but I think it could be applied to this problem, I hope help you, it is the same I have a list of element and every li element has inside two div element and what I want is to apply the same style in step of every 2 elements, I mean, 1+2 Same Style and 3+4 Other Style and so on, 5+6 the same style of the 1+2. So here is What I did.

HTML

<ul>
  <li>
    <div class="photo">PHOTO</div>
    <div class="text">TEXT</div>
  </li>
  <li>
    <div class="photo">PHOTO</div>
    <div class="text">TEXT</div>
  </li>
  <li>
    <div class="photo">PHOTO</div>
    <div class="text">TEXT</div>
  </li>
  <li>
    <div class="photo">PHOTO</div>
    <div class="text">TEXT</div>
  </li>
  <li>
    <div class="photo">PHOTO</div>
    <div class="text">TEXT</div>
  </li>
  <li>
    <div class="photo">PHOTO</div>
    <div class="text">TEXT</div>
  </li>
  <li>
    <div class="photo">PHOTO</div>
    <div class="text">TEXT</div>
  </li>
  <li>
    <div class="photo">PHOTO</div>
    <div class="text">TEXT</div>
  </li>
</ul>

Javascript

var row = 0;
$( "li" ).each(function( index ) {
  // Here is when you loop every two elements
  if ( index % 2 == 0)
  {
    if (row % 2 == 0 )
    {
      //console.log("index "+index + " row" + row);
      first_element = $( "ul li:eq("+index+")" ).addClass( "blue-bg" );
      second_element = $( "ul li:eq("+(index+1)+")" ).addClass( "blue-bg" );
      $(first_element).find('.photo').addClass( "pull-left" );
      $(first_element).find('.text').addClass( "pull-right" );
      $(second_element).find('.photo').addClass( "pull-left" );
      $(second_element).find('.text').addClass( "pull-right" );
      row = 1; // make row value odd
    }
    else
    {
      //console.log("index "+index + " row" + row);
      third_element = $( "ul li:eq("+index+")" ).addClass( "red-bg" );
      four_element = $( "ul li:eq("+(index+1)+")" ).addClass( "red-bg" );
      $(third_element).find('.photo').addClass( "pull-right" );
      $(third_element).find('.text').addClass( "pull-left" );
      $(four_element).find('.photo').addClass( "pull-right" );
      $(four_element).find('.text').addClass( "pull-left" );
      row = 0;  // make row vale even
    }
  }
});

This is the jsfiddle

Answer 3

Let's jump to the assumption that you can fix the HTML to make it valid, and it looks like:

<div class='feature'></div>
<div class='feature'></div>
<div class='feature'></div>
<div class='feature'></div>
<div class='feature'></div>
<div class='feature'></div>

You can then use a selector like:

$("div:odd")

or

$("div:even")

more like:

$("div:even").children(':even');

NOTE: 0 based index, so 2,4,etc (normal count) are ODD...

Answer 4

I used this code to format a set of divs into a two column table:

$('.feature:even').each(function () {
    $(this).add($(this).next()).wrapAll("<tr>");
});
$('.feature').wrap('<td>');
$('tr').wrapAll('<table>');

Answer 5

var pairs = [];
$('div.feature').each(function(i, div) {
  var i_over_2 = Math.floor(i / 2);
  if (!pairs[i_over_2]) pairs[i_over_2] = $();
  pairs[i_over_2] = pairs[i_over_2].add(div);
});
$.each(pairs, function(i, p) {
  p.doSomethingToAPair();
});

The idea is to build up an array of jQuery objects.

edit looks like 1.4 added "$()" to get an empty jQuery object.

edit again durr Javascript has floats :-)

Hey @Adam: if we had this jQuery extension (this is a toy version of course):

jQuery.fn.zip = function(s) {
  var o = $(s);
  return this.map(function(i, e) {
    return $(e).add($(o[i]));
  });
};

then we could build the "pairs" array like this:

var pairs = $('div.feature:even').zip('div.feature:odd');