GSON: How to move fields to parent object

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暖寄归人
暖寄归人 2020-12-20 17:40

I\'m using Google GSON to transform my Java object to JSON.

Currently I\'m having the following structure:

\"Step\": {
  \"start_name\": \"Start\",
          


        
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4条回答
  • 2020-12-20 18:06

    You can probably do this by writing, and then registering a custom serializer for Step, and making sure inside it you work with Duration etc, instead of Data.

    // registering your custom serializer:
    GsonBuilder builder = new GsonBuilder ();
    builder.registerTypeAdapter (Step.class, new StepSerializer ());
    Gson gson = builder.create ();
    // now use 'gson' to do all the work
    

    The code for the custom serializer below, I'm writing off the top of my head. It misses exception handling, and might not compile, and does slow things like create instances of Gson repeatedly. But it represents the kind of thing you'll want to do:

    class StepSerializer implements JsonSerializer<Step>
    {
      public JsonElement serialize (Step src,
                                    Type typeOfSrc,
                                    JsonSerializationContext context)
        {
          Gson gson = new Gson ();
          /* Whenever Step is serialized,
          serialize the contained Data correctly.  */
          JsonObject step = new JsonObject ();
          step.add ("start_name", gson.toJsonTree (src.start_name);
          step.add ("end_name",   gson.toJsonTree (src.end_name);
    
          /* Notice how I'm digging 2 levels deep into 'data.' but adding
          JSON elements 1 level deep into 'step' itself.  */
          step.add ("duration",   gson.toJsonTree (src.data.duration);
          step.add ("distance",   gson.toJsonTree (src.data.distance);
          step.add ("location",   gson.toJsonTree (src.data.location);
    
          return step;
        }
    }
    
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  • 2020-12-20 18:08

    Ran into the same problem. The answer from @ArjunShunkar pointed me in the right direction. I fixed it writing a custom Serializer, but slightly different:

    public class StepSerializer implements JsonSerializer<Step> {
        @Override
        public JsonElement serialize(Step src, Type typeOfSrc, JsonSerializationContext context) {
            JsonObject step = new JsonObject();
            step.add ("start_name", context.serialize(src.start_name);
            step.add ("end_name",   context.serialize(src.end_name);
    
            JsonObject data = context.serialize(src.data).getAsJsonObject();
            data.entrySet().forEach(entry -> {
                step.add(entry.getKey(), entry.getValue());
            });
    
            return step;
        }
    }
    

    This could be improved further, the "start_name" and "end_name" props are still hardcoded. Could be removed by going over the entrySet for the root object and excluding 'data' there, leaving only the element that needs to be unwrapped hardcoded.

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  • 2020-12-20 18:15

    I don't think there is beautifull way to do it in gson. Maybe get java object (Map) from initial json, remove data, put duration and serialize to json:

    Map initial = gson.fromJson(initialJson);
    
    // Replace data with duration in this map
    Map converted = ...
    
    String convertedJson = gson.toJson(converted);
    
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  • 2020-12-20 18:17

    In such case I register TypeAdapter for nested data field. Within the the adapter data's fields are added to parent object. No need to create adapter for enclosing class.

    public class Step {
        private String startName;
        private endName;
        @JsonAdapter(JsonFlatMapAdapter.class)
        private Map<String, Object> data;
        ...
    }
    
    public class JsonFlatMapAdapter extends TypeAdapter<Map<String, Object>> {
    
        @Override
        public void write(JsonWriter out, Map<String, Object> value) throws IOException {
            out.nullValue();
            Gson gson = new Gson();
            value.forEach((k,v) -> {
                try {
                    out.name(k).jsonValue(gson.toJson(v));
                } catch (IOException e) {
                }
            });
        }
    
        @Override
        public Map<String, Object> read(JsonReader in) throws IOException {
            return null;
        }
    
    }
    
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