Extract X number of words surrounding a given search string within a string

Question

I am looking for a way to extract X number of words on either side of a given word in a search.

For example, if a user enters \"inmate\" as a search word and the MyS

Answer 1

I would use this regex for php which also takes UTF8 characters into account

'~(?:[\p{L}\p{N}\']+[^\p{L}\p{N}\']+){0,5}<search word>(?:[^\p{L}\p{N}\']+[\p{L}\p{N}\']+){0,5}~u'

In this case '~' is the delimiter and the modificator 'u' at the end identifies the regex is UTF8 interpreted.

please see a documentation about the Unicode Regex identifiers here:

http://www.regular-expressions.info/refunicode.html

Answer 2

You might not be able to fully solve this problem with regex. There are too many possibilities of other characters between the words...

But you can try this regex:

((?:\S+\s*){0,5}\S*inmate\S*(?:\s*\S+){0,5})

See here : rubular

You might also want to exclude certain characters as they are not counted as words. Right now the regex counts any sequence of non space characters that are surrounded by spaces as word.

To match only real words:

((?:\w+\s*){0,5}<search word>(?:\s*\w+){0,5})

But here any non word character (,". etc.) brakes the matching.

So you can go on...

((?:[\w"',.-]+\s*){0,5}["',.-]?<search word>["',.-]?(?:\s*[\w"',.-]+){0,5})

This would also match 5 words with one of "',.- around your search term.

To use it in php:

$sourcestring="For example, if a user enters \"inmate\" as a search word and the MySQL";
preg_match_all('/(?:\S+\s*){0,5}\S*inmate\S*(?:\s*\S+){0,5}/s',$sourcestring,$matches);
echo $matches[0][0]; // you might have more matches, they will be in $matches[0][x]