How do you escape a double quote character inside a MS SQL \'contains\' function?
SELECT decision
FROM table
WHERE CONTAINS(decision, \'34\" AND wide\')
From documentation:
Punctuation is ignored. Therefore,
CONTAINS(testing, "computer failure")
matches a row with the value, "Where is my computer? Failure to find it would be expensive."
Since FULLTEXT
does not even index the punctuation, you'll need to fine-filter your results using LIKE
:
SELECT decision
FROM table
WHERE CONTAINS(decision, '34 AND wide')
AND decision LIKE '%34"%'
This will preserve the benefits of fulltext.
The above answer does not work in SQL Server 2008 if your string is for a single-digit number.
This works:
SELECT partdescription
FROM table
WHERE CONTAINS(partdescription, '10')
AND decision LIKE '%10"%'
This doesn't work:
SELECT partdescription
FROM table
WHERE CONTAINS(partdescription, '6')
AND decision LIKE '%6"%''
EDIT: Explanation of why a single digit may not be indexed.
If the SYSTEM stop word (or noise word) list is being used it contains each of the numeric digits as words to be ignored. You can change the contents of the Stop Word list or you can turn off the Stop Words altogether.
ALTER FULLTEXT INDEX ON dbo.my_ft_table SET STOPLIST = OFF;
Once one of these changes is made, the text affected must be reindexed before the single digits become searchable. After the reindexing it will indeed be possible to search for '6'.