itoa function problem

Question

I\'m working on Eclipse inside Ubuntu environment on my C++ project.

I use the itoa function (which works perfectly on Visual Studio) and the compiler c

Answer 1

itoa depends on compiler, so better use the following methods :-

method 1 :If you are using c++11, just go for std::to_string. It will do the trick.

method 2 :sprintf works for both c & c++. ex- ex - to_string

#include <bits/stdc++.h>
using namespace std;
int main ()
{
  int i;
  char buffer [100];
  printf ("Enter a number: ");
  scanf ("%d",&i);

  string str = to_string(i);
  strcpy(buffer, str.c_str());

  cout << buffer << endl;
  return 0;
}

Note - compile using -std=c++0x.

C++ sprintf:

int main ()
{
int i;
  char buffer [100];
  printf ("Enter a number: ");
  scanf ("%d",&i);
  sprintf(buffer, "%d", i);
  return 0;
}`

Answer 2

you may use sprintf

char temp[5];
temp[0]="h"
temp[1]="e"
temp[2]="l"
temp[3]="l"
temp[5]='\0'
sprintf(temp+4,%d",9)
cout<<temp;

output would be :hell9

Answer 3

www.cplusplus.com says:

This function is not defined in ANSI-C and is not part of C++, but is supported by some compilers.

Therefore, I'd strongly suggest that you don't use it. However, you can achieve this quite straightforwardly using stringstream as follows:

stringstream ss;
ss << myInt;
string myString = ss.str();

Answer 4

itoa() is not part of any standard so you shouldn't use it. There's better ways, i.e...

C:

int main() {
    char n_str[10];
    int n = 25;

    sprintf(n_str, "%d", n);

    return 0;
}

C++:

using namespace std;
int main() {
    ostringstream n_str;
    int n = 25;

    n_str << n;

    return 0;
}

Answer 5

Did you include stdlib.h? (Or rather, since you're using C++, cstdlib)

Answer 6

Boost way:

string str = boost::lexical_cast<string>(n);