Arithmetic operation resulted in an overflow. (Adding integers)

Question

I can\'t understand this error:

In this call to method SetVolume, Volume = 2055786000 and size = 93552000. Volume is an Integer pr

Answer 1

2055786000 + 93552000 = 2149338000, which is greater than 2^31. So if you're using signed integers coded on 4 bytes, the result of the operation doesn't fit and you get an overflow exception.

Answer 2

This error occurred for me when a value was returned as -1.#IND due to a division by zero. More info on IEEE floating-point exceptions in C++ here on SO and by John Cook

For the one who has downvoted this answer (and did not specify why), the reason why this answer can be significant to some is that a division by zero will lead to an infinitely large number and thus a value that doesn't fit in an Int32 (or even Int64). So the error you receive will be the same (Arithmetic operation resulted in an overflow) but the reason is slightly different.