PHP subtract 1 month from date formatted with date ('m-Y')

Question

I\'m trying to subtract 1 month from a date.

$today = date(\'m-Y\');

This gives: 08-2016

How can I subtract a month to get 07

Answer 1

Warning! The above-mentioned examples won't work if call them at the end of a month.

<?php
$now = mktime(0, 0, 0, 10, 31, 2017);
echo date("m-Y", $now)."\n";
echo date("m-Y", strtotime("-1 months", $now))."\n";

will output:

10-2017
10-2017

The following example will produce the same result:

$date = new DateTime('2017-10-31 00:00:00');
echo $date->format('m-Y')."\n";
$date->modify('-1 month');
echo $date->format('m-Y')."\n";

Plenty of ways how to solve the issue can be found in another thread: PHP DateTime::modify adding and subtracting months

Answer 2

First change the date format m-Y to Y-m

    $date = $_POST('date'); // Post month
    or
    $date = date('m-Y'); // currrent month

    $date_txt = date_create_from_format('m-Y', $date);
    $change_format = date_format($date_txt, 'Y-m');

This code minus 1 month to the given date

    $final_date = new DateTime($change_format);
    $final_date->modify('-1 month');
    $output = $final_date->format('m-Y');

Answer 3

I used this to prevent the "last days of month"-error. I just use a second strtotime() to set the date to the first day of the month:

<?php
echo $newdate = date("m-Y", strtotime("-1 months", strtotime(date("Y-m")."-01")));

Answer 4

Try this,

$today = date('m-Y');
$newdate = date('m-Y', strtotime('-1 months', strtotime($today))); 
echo $newdate;