When I define a StringBuffer
variable with new
, this string is not added to the String pool, right?
Now, when I define another String
buf.append("XXX")
followed by buf.toString(), and then returning the string
to the pool. With the pool in place, only one StringBuffer
object is ever allocated.
"XXX" in StrPrev.append("XXX")
is a string literal that is interned at class loading time (class loading time of the class that contains the code).
"XXX" is not added to the pool by the StringBuffer
.
From the JLS section 3.10.5:
Moreover, a string literal always refers to the same instance of class String. This is because string literals - or, more generally, strings that are the values of constant expressions (§15.28) - are "interned" so as to share unique instances
From the JLS section 12.5:
Loading of a class or interface that contains a String literal (§3.10.5) may create a new String object to represent that literal. (This might not occur if the same String has previously been interned (§3.10.5).)
When I define a StringBuffer variable with new, this string is not added to the String pool, right?
Creating a StringBuffer
does not create a String
at all.
Now, when I define another StringBuffer but not with new, I define it as StrPrev.append("XXX") suddenly it is.
This is totally confused:
When you call strBuff.append("XXX")
you are NOT defining a new StringBuffer
. You are updating the existing StringBuffer
that strBuff
refers to. Specifically, you are adding extra characters to the end of the buffer.
You only get a new String
from the StringBuffer
when you call strBuff.toString()
.
You only add a String
to the string pool when you call intern()
on the String
. And that only adds the string to the pool if there is not already an equal string in the pool.
The String object that represents the literal "XXX"
is a member of the string pool. But that happens (i.e. the String is added to the pool) when the class is loaded, not when you execute the append
call.
(If you teacher told you that StringBuffer puts strings into the Java string pool, he / she is wrong. But, given your rather garbled description, I suspect that you actually misheard or misunderstood what your teacher really said.)
Actually your teacher is referring to XXX
. which goes to StringPool because all string literals written in java program goes to StringPool while execution...