REGEX Remove Space

Question

I want to creating regex to remove some matching string, the string is phone number

Example user input phone number like this:

+jfalkjfkl saj f62 81 78

Answer 1

I don't know what language you plan on using this in, but you can replace this pattern: [^\d]+, with an empty string should accomplish this. It'll remove everything that's not a number.

Answer 2

Use a look-behind and a look-ahead to assert that digits must precede/follow the space(s):

(?<=\d) +(?=\d)

The entire regex matches the spaces, so no need to reference groups in your replacement, just replace with a blank.

Answer 3

Using PCRE regexes, you should be able to simply remove anything matching \D+. Example:

echo "+jfalkjfkl saj f62 81 7876 asdadad30 asasda36" | perl -pe 's/\D+//g'

prints:

628178763036

Answer 4

It would appear that you need two operations:

1. Remove everything that is neither a blank nor a digit:

   s/[^ \d]//g;
   

2. Remove all extra blanks:

   s/  +/ /g;
   

   If you need to remove leading and trailing blanks too:

   s/^ //;
   s/ $//;
   

   (after the replace multiple blanks with a single blank).

You can use \s to represent more space-like characters than just a blank.

Answer 5

If you make a replace you can reconstruct the phone number with the space between numbers:

search:  \D*(\d+)\D*?(\s?)
replace: $1$2