Select Varchar as Date

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攒了一身酷
攒了一身酷 2020-12-20 07:02

I want to select a varchar field as a date field

For example a field has this value \"30.12.2011 21:15:03\"

and when i select this

select DAT         


        
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  • 2020-12-20 07:35

    You ask about getting the date part of a timestamp field, but what your question is actually about is filtering on the date of a timestamp field. There is a much simpler method of accomplishing that: you can use the knowledge that all the possible timestamps on a specific date won't have any timestamps for different dates between them.

    select DATE
    from TABLE
    where DATE >= '30.12.2011' and DATE < '31.12.2011'
    

    Your edit explains that you haven't got a timestamp field at all. Nevertheless, a similar approach may still work:

    select DATE
    from TABLE
    where DATE LIKE '30.12.2011 %'
    

    Or the Firebird-specific

    select DATE
    from TABLE
    where DATE starting with '30.12.2011 '
    
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  • 2020-12-20 07:35

    Here is the answere to my question:

    CAST
    (
    SUBSTRING
    (field FROM 1 FOR 2)
    ||'.'||
    SUBSTRING
    (field FROM 4 FOR 2)
    ||'.'||
    SUBSTRING
    (field FFROM 7 FOR 4)
    AS DATE)
    

    This took me 5 hours to find this out, maybe there should be a "-" instead of "." but it works.

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  • 2020-12-20 07:38

    select DATE from TABLE where cast(DATE as date) = '30.12.2011'

    Date field is a timestamp

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  • 2020-12-20 07:50

    Assuming the field is a date field, use the DATE introducer combined with yyyy-mm-dd (or TIMESTAMP with time as well).

    So use:

    select datefield from sometable where datefield = DATE '2011-12-30'
    

    Technically you can leave off the introducer, but it is 'correcter' in the light of the SQL standard.

    Assuming a TIMESTAMP field, you won't get results unless the timestamp is (always) at 00:00:00.0000 (in which case it should have been a DATE instead).

    For the comparison to work, you need to use either BETWEEN, eg:

    select timestampfield from sometable 
    where timestampfield BETWEEN '2011-12-30 00:00:00.0000' AND '2011-12-30 23:59:59.9999'
    

    or truncate the timestamp to a date (this may adversely effect performance if the timestamp is indexed, because then the index can no longer be used), eg:

    select timestampfield from sometable
    where CAST(timestampfield AS DATE) = '2011-12-30'
    

    If the date is stored in a VARCHAR field (which in itself is a bad idea), there are several solutions, first is to handle it as date manipulation:

    select varcharfield from sometable
    where CAST(CAST(varcharfield AS TIMESTAMP) AS DATE) = '2011-12-30'
    

    The double cast is required if you have a time-component in VARCHARFIELD as well. This assumes dates in the supported format listed below. If you use BETWEEN as above, you can use a single cast to timestamp)

    The other solution (as suggested by hvd) is to treat it purely as string manipulation, for example:

    select varcharfield from sometable
    where varcharfield STARTING WITH '30.12.2011'
    

    This has its own set of problems if you want to select ranges. Bottomline: use a real TIMESTAMP field!

    Note that Firebird supports multiple formats:

    • yyyy-mm-dd, eg 2014-05-25 (ISO-8601 format, probably best to use as it reduces confusion)
    • dd.mm.yyyy, eg 25.05.2014
    • mm/dd/yyyy, eg 05/25/2014
    • mm-dd-yyyy, eg 05-25-2014
    • dd mmm yyyy, eg 25 MAY 2014 (+ variations with a -, . or / as separator)
    • mmm dd yyyy, eg MAY 25 2014 (+ variations with a -, . or / as separator)
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