I\'m creating a form in Play using the following code:
@inputText(loginForm(\"password\"),
\'type -> \"password\",
You can achieve this by creating a custom FieldConstructor (see http://www.playframework.com/documentation/2.3.x/ScalaCustomFieldConstructors).
Create a new file views/helper/myPlainFieldConstructor.scala.html
that contains the following:
@(elements: helper.FieldElements)
@elements.input
[For reference, you can see the default field constructor here.]
Then, in the view template containing your form:
@import helper._
@implicitField = @{ FieldConstructor(myPlainFieldConstructor.f) }
[...]
@form(action = ...) {
@inputPassword(loginForm("password"))
}
Note: If you really need value=""
, you can add 'value -> ""
to the helper's arguments, i.e.
@inputPassword(loginForm("password"), 'value -> "")
Or further customize the HTML with the generic input
helper, as in:
@input(loginForm("password")) { (id, name, value, args) =>
<input type="password" name="@name" id="@id" value="" @toHtmlArgs(args)>
}