Firefox [removed] Why does .all not work?

Question

In IE, I can go like:

var x = document.getElementById(\"header\");

alert(x.all[0].tagName);

If I try that in Firefox, I get the error \"al

Answer 1

.all is a Microsoft-specific extension to the DOM, and is not supported by any other browsers (except Opera, I believe, who simulate it in order to improve compatibility with sites written for IE).

You can use things like x.children and x.childNodes, or x.getElementById() and x.getElementsByTagName() to reference elements below the current one in the tree, depending on your usage. I suspect in this case x.children is what you're after.

Answer 2

all would be the name of an array. It is not a native javascript keyword.

You may want to look at childNodes instead.