All combinations of all sizes?

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北海茫月
北海茫月 2020-12-19 23:14

There are thousands of results on SO when I search for \"vector combinations in R\" but I can\'t find the answer to my question. Apologies if it is a duplicate:

I ha

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  • 2020-12-20 00:05

    If you prefer compact code

    Map(combn, list(x), seq_along(x))
    ## [[1]]
    ##      [,1] [,2] [,3] [,4]
    ## [1,]    1    2    3    4
    
    ## [[2]]
    ##      [,1] [,2] [,3] [,4] [,5] [,6]
    ## [1,]    1    1    1    2    2    3
    ## [2,]    2    3    4    3    4    4
    
    ## [[3]]
    ##      [,1] [,2] [,3] [,4]
    ## [1,]    1    1    1    2
    ## [2,]    2    2    3    3
    ## [3,]    3    4    4    4
    
    ## [[4]]
    ##      [,1]
    ## [1,]    1
    ## [2,]    2
    ## [3,]    3
    ## [4,]    4
    

    To avoid repetition, you'll have to deal with nested list but you can simplify the result using unlist

    res <- Map(combn, list(x), seq_along(x), simplify = FALSE)
    unlist(res, recursive = FALSE)
    ## [[1]]
    ## [1] 1
    
    ## [[2]]
    ## [1] 2
    
    ## [[3]]
    ## [1] 3
    
    ## [[4]]
    ## [1] 4
    
    ## [[5]]
    ## [1] 1 2
    
    ## [[6]]
    ## [1] 1 3
    
    ## [[7]]
    ## [1] 1 4
    
    ## [[8]]
    ## [1] 2 3
    
    ## [[9]]
    ## [1] 2 4
    
    ## [[10]]
    ## [1] 3 4
    
    ## [[11]]
    ## [1] 1 2 3
    
    ## [[12]]
    ## [1] 1 2 4
    
    ## [[13]]
    ## [1] 1 3 4
    
    ## [[14]]
    ## [1] 2 3 4
    
    ## [[15]]
    ## [1] 1 2 3 4
    
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  • 2020-12-20 00:09

    Perhaps combn in conjunction with lapply might be helpful:

    x <- 1:4
    lapply(seq_along(x), function(y) combn(x, y))
    # [[1]]
    #      [,1] [,2] [,3] [,4]
    # [1,]    1    2    3    4
    # 
    # [[2]]
    #      [,1] [,2] [,3] [,4] [,5] [,6]
    # [1,]    1    1    1    2    2    3
    # [2,]    2    3    4    3    4    4
    # 
    # [[3]]
    #      [,1] [,2] [,3] [,4]
    # [1,]    1    1    1    2
    # [2,]    2    2    3    3
    # [3,]    3    4    4    4
    # 
    # [[4]]
    #      [,1]
    # [1,]    1
    # [2,]    2
    # [3,]    3
    # [4,]    4
    

    As @Roland points out, there is also a simplify argument to combn that when set to FALSE would create a nested list of individual column vectors rather than a matrix of all the results. For example, instead of list item [[3]] above being presented as a matrix, if you used lapply(seq_along(x), function(y) combn(x, y)), for the combinations of length 3 you would get:

    # [[3]]
    # [[3]][[1]]
    # [1] 1 2 3
    # 
    # [[3]][[2]]
    # [1] 1 2 4
    # 
    # [[3]][[3]]
    # [1] 1 3 4
    # 
    # [[3]][[4]]
    # [1] 2 3 4
    
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