char array not assignable

Question

Okay, so I want to save a word in a char array but it gives me a error

Here\'s my code

#include 
#include  
#i         


        

Answer 1

 class = "Ranger";

should be

strcpy(class,"Ranger");

Fix the same in all the places. char arrays are not assignable

Answer 2

see this is not only for character array , this implies for all type of arrays but the question aries why?,when we can assign other variable why not array the thing is:- suppose we have:

int a[size];
a = {2,3,4,5,6};

because here the name of an array mean address of the first location of an array

printf("%p",a); // let suppose the output is 0x7fff5fbff7f0

We are saying by that

0x7fff5fbff7f0 = something; which is not correct yes we can do a[0] = something , now it saying assign the value of array at 0th location.

Answer 3

Yes char arrays are not assignable just as all arrays aren't. You should use strcpy for example

strcpy(class, "Warrior");

and so on.

Also, you don't need to declare char class[30]; the longest string I see in your code is "undefined" so

char class[10];

should be ok, 9 characters of "undefined" + 1 null terminating byte '\0'.

And you should prevent buffer overflow with scanf this way

scanf("%1s", class);

since you only want to read 1 character, also the comparison should be simpler just

if (class[0] == 'M')
    strcpy(class, "Mage");

or even thsi would be more readable

classchosen = 1;
switch (class[0])
{
case 'M':
    strcpy(class, "Mage");
    break;
case 'R':
    strcpy(class, "Ranger");
    break;
case 'W':
    strcpy(class, "Warrior");
    break;
default:
    classchosen = 0;
}

and finally check that scanf actually succeeded, it returns the number of arguments matched so in your case a check would be like

if (scanf("%1s", class) == 1) ...

Answer 4

switch class = "Warrior"; to strcpy(class, "warrior");

switch class = "Mage"; to strcpy(class, "Mage");

switch class = "Ranger"; to strcpy(class, "Ranger");

switch class = "undefined"; to strcpy(class, "undefined");

and it should work !