What's the right way to overload the stream operators << >> for my class?

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礼貌的吻别
礼貌的吻别 2020-12-19 09:49

I\'m a bit confused about how to overload the stream operators for my class in C++, since it seems they are functions on the stream classes, not on my class. What\'s the no

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  • 2020-12-19 10:31

    The other answers are right. In case it helps you, here's a code example (source):

    class MyClass {
      int x, y;
    public:
      MyClass(int i, int j) { 
         x = i; 
         y = j; 
      }
      friend ostream &operator<<(ostream &stream, MyClass ob);
      friend istream &operator>>(istream &stream, MyClass &ob);
    };
    
    ostream &operator<<(ostream &stream, MyClass ob)
    {
      stream << ob.x << ' ' << ob.y << '\n';
    
      return stream;
    }
    
    istream &operator>>(istream &stream, MyClass &ob)
    {
      stream >> ob.x >> ob.y;
    
      return stream;
    }
    
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  • 2020-12-19 10:33

    Your implementation is fine. The only additional step you need to perform is to declare your operator as a friend in Thing:

    class Thing {
    public:
      friend istream& operator>>(istream&, Thing&);
      ...
    }
    
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  • 2020-12-19 10:43

    You make your operator>> a friend of the Thing class.

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  • 2020-12-19 10:44

    There are several approaches and the right one really depends on what the class does.

    Quite often it makes sense to have public API that allows reading the information, in which case the streaming operators do not need to access privates.

    Probably the most popular approach is declaring the streaming functions friends of the class.

    My favorite is providing a public Boost.Serialization style template function that can be used for streaming either way, as well as for other things.

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