Compiling to GHC Core

Question

I would like to create a frontend for a simple language that would produce GHC Core. I would like to then take this output and run it through the normal GHC pipeline. Accord

Answer 1

There's still no way to read External Core files, whether via the ghc command or the API. Sorry :(

It's probably theoretically possible to build the Core syntax tree up from your representation using the GHC API, but that sounds very painful. I would recommend targeting some other backend. You don't necessarily have to stop using GHC; straightforward Haskell with unboxed types and unsafeCoerce lets you get pretty close to the resulting Core, so you could define your own simple "Core-ish" language and compile it to that. (Indeed, you could probably even compile GHC Core itself, but that's a bit too meta for my tastes.)

Answer 2

Note that Core is an explicitly typed language, which can make it quite difficult to generate from other languages (the GHC type checker has inferred all the types so it's no problem there). For example, the usual identity function (id = \x -> x :: forall a. a -> a) becomes

id = \(a :: *) (x :: a) -> a

where a is a type variable of kind *. It is a term-level place-holder for the type-level forall binding. Similarly, when calling id you need to give it a type as its first argument, so the Haskell expression (id 42) gets translated into (id Int 42). Such type bindings and type applications won't be present in the generated machine code, but they are useful to verify compiler transformations are correct.

On the bright side, it might be possible to just generate Haskell -- if you can generate the code in such a way that GHC will always be able to determine its type then you are essentially just using a tiny subset of Haskell. Whether this can work depends very much on your source language, though.