Iterations through pixels in an image are terribly slow with python (OpenCV)

Question

I am aware of iterating through pixels and accessing their values using OpenCV with C++. Now, i am trying to learn python myself and i tried to do the same

Answer 1

(note: I'm not familiar with opencv, but this appears to be a numpy issue)

The "terribly slow" part is that you're looping in python bytecode, rather than letting numpy loop at C speed.

Try directly assigning to a (3-dimensional) slice that masks the region you want to zero out.

import numpy as np

example = np.ones([500,500,500], dtype=np.uint8)

def slow():
     img = example.copy()
     height, width, depth = img.shape
     for i in range(0, height):             #looping at python speed...
         for j in range(0, (width//4)):     #...
             for k in range(0,depth):       #...
                 img[i,j,k] = 0
     return img


def fast():
     img = example.copy()
     height, width, depth = img.shape
     img[0:height, 0:width//4, 0:depth] = 0 # DO THIS INSTEAD
     return img 

np.alltrue(slow() == fast())
Out[22]: True

%timeit slow()
1 loops, best of 3: 6.13 s per loop

%timeit fast()
10 loops, best of 3: 40 ms per loop

The above shows zeroing out the left side; doing the same for the right side is an exercise for the reader.

If the numpy slicing syntax trips you up, I suggest reading through the indexing docs.