Set Union in pandas

Question

I have two columns which I stored sets in my dataframe.

I want to perform set union on the two columns using fast vectorized operation

df[\'union\']          


        

Answer 1

This is the best I could come up with:

# method 1
df.apply(lambda x: x.set1.union(x.set2), axis=1)

# method 2
df.applymap(list).sum(1).apply(set)

Wow!

I expected the method 2 to be quicker. Not so!

Example

df = pd.DataFrame([[{1, 2, 3}, {3, 4, 5}] for _ in range(3)],
                  columns=list('AB'))
df

df.apply(lambda x: x.set1.union(x.set2), axis=1)

0    {1, 2, 3, 4, 5}
1    {1, 2, 3, 4, 5}
2    {1, 2, 3, 4, 5}

Answer 2

For these operations pure Python may be more efficient.

%timeit pd.Series([set1.union(set2) for set1, set2 in zip(df['A'], df['B'])])
10 loops, best of 3: 43.3 ms per loop

%timeit df.apply(lambda x: x.A.union(x.B), axis=1)
1 loop, best of 3: 2.6 s per loop

If we could use +, it would probably take half the time (inheritance may not worth it):

%timeit df['A'] - df['B']
10 loops, best of 3: 22.1 ms per loop

%timeit pd.Series([set1.difference(set2) for set1, set2 in zip(df['A'], df['B'])])
10 loops, best of 3: 35.7 ms per loop

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DataFrame for timings:

import pandas as pd
import numpy as np
l1 = [set(np.random.choice(list('abcdefg'), np.random.randint(1, 5))) for _ in range(100000)]
l2 = [set(np.random.choice(list('abcdefg'), np.random.randint(1, 5))) for _ in range(100000)]

df = pd.DataFrame({'A': l1, 'B': l2})