How to sort a javascript array of numbers [duplicate]

Answer 1

<script type="text/javascript">

function sortNumber(a,b)
{
return a - b;
}

var n = ["10", "5", "40", "25", "100", "1"];
document.write(n.sort(sortNumber));

</script> 

Answer 2

Usually works for me:

a.sort(function(a,b){ 
  return a - b;
});

Answer 3

You can pass in a comparator function to sort.

> a.sort(function(a, b) { return a < b ? -1 : a > b ? 1 : 0; });
  [1, 3, 23, 100]

Answer 4

So if you write the sorting function, it will work.

[1, 23, 100, 3].sort(function(a, b){
    if (a > b)
        return 1;
    if (a < b)
        return -1;
    return 0
});

Answer 5

Here is a solution to sort a Javascript array in ascending order

function bubblesort(array){

    var done = false;
    while(!done){
        done = true;
        for(var i = 1; i< array.length; i++){
            if(array[i -1] > array[i]){
                done = false;
                var tmp = array[i-1];
                array[i-1] = array[i];
                array[i] = tmp;
            }
        }
    }
    return array;
}
var numbers = [2, 11, 1, 20, 5, 35];
bubblesort(numbers);

Answer 6

Use a custom sort function.

a = [1, 23, 100, 3];
a.sort(function(a,b){ return a-b; });