I need to replace a word in a string looking like \"duh duh something else duh\". I only need to replace the second \"duh\", but the first and the last ones need to stay unt
Will something like this work?
System.out.println(
"1 duh 2 duh duh 3 duh"
.replaceFirst("(duh.*?)duh", "$1bleh")
); // prints "1 duh 2 bleh duh 3 duh"
If you just want to replace the second occurrence of a pattern in a string, you really don't need this "starting from" index calculation.
As a bonus, if you want to replace every other duh
(i.e. second, fourth, sixth, etc), then just invoke replaceAll
instead of replaceFirst
.
An alternative using Matcher:
String input = "duh duh something else duh";
Pattern p = Pattern.compile("duh");
Matcher m = p.matcher(input);
int startIndex = 4;
String output;
if (m.find(startIndex)) {
StringBuffer sb = new StringBuffer();
m.appendReplacement(sb, "dog");
m.appendTail(sb);
output = sb.toString();
} else {
output = input;
}
What about something like this:
String replaceFirstFrom(String str, int from, String regex, String replacement)
{
String prefix = str.substring(0, from);
String rest = str.substring(from);
rest = rest.replaceFirst(regex, replacement);
return prefix+rest;
}
// or
s.substring(0,start) + s.substring(start).replaceFirst(search, replace);
just 1 line of code ... not a whole method.