Help with regexp replacing every second comma in the string

Question

I have a string of that displays like this....

1235, 3, 1343, 5, 1234, 1

I need to replace every second comma with a semicolon

i.e.

1235, 3;

Answer 1

var s='1235, 3, 1343, 5, 1234, 1';

s=s.replace(/([^,]+,[^,]+),/g,'$1;')

match anything that is not a comma, followed by a comma, followed by anything that is not a comma, and a comma.

replace everthing inside the parens (which doesn't include the last comma) with itself ('$1'), and add a semicolon in place of that comma.

Answer 2

var myregexp = /(\d+,\s\d+),/g;
result = subject.replace(myregexp, "$1;");

Answer 3

var s = '1235, 3, 1343, 5, 1234, 1';
var result = s.replace(/(,[^,]*),/g,"$1;");

Answer 4

var foo = "1235,3,1343,5,1234,1".replace(/(.\*?),(.\*?),/g, "$1,$2;");

console.log(foo)

Answer 5

How about:

var regex = /(\d+),\s(\d+),\s/g;
var str = '1235, 3, 1343, 5, 1234, 1'; 
alert(str.replace(regex, '$1, $2; ')); // 1235, 3; 1343, 5; 1234, 1

Answer 6

'1235, 3, 1343, 5, 1234, 1'.replace(/([0-9]+),\s([0-9]+),\s/g, '$1, $2; ')