Given the following list:
l <- list(\"foo123\"=c(1:3), \"foo456\"=5, \"foo789\"=8)
print(l)
# $foo123
# [1] 1 2 3
#
# $foo456
# [1] 5
#
# $foo789
We can try setting the names after unlisting. We also use use.names=FALSE
to avoid creating and rewriting a vector of names (MartinMorgan):
setNames(unlist(l, use.names=F),rep(names(l), lengths(l)))
#foo123 foo123 foo123 foo456 foo789
# 1 2 3 5 8
However, note that in most cases, duplicate names will lead to ambiguity and possibly errors. Given your example, if we now attempt to subset using the name "foo123"
R outputs only the first instance:
o <- setNames(unlist(l, use.names=F),rep(names(l), lengths(l)))
o["foo123"]
# foo123
# 1
This doesn't exactly answer your question, but an alternative that you can consider would be to go from a list
to a "long" data.frame
or data.table
.
This is easily achieved with stack
in base R or melt
from "reshape2" or "data.table".
Example:
stack(l)
# values ind
# 1 1 foo123
# 2 2 foo123
# 3 3 foo123
# 4 5 foo456
# 5 8 foo789
library(data.table)
melt(l)
# value L1
# 1 1 foo123
# 2 2 foo123
# 3 3 foo123
# 4 5 foo456
# 5 8 foo789
Then, if you really wanted a named vector, you could always do:
o <- data.table::melt(l)
setNames(o$value, o$L1)
# foo123 foo123 foo123 foo456 foo789
# 1 2 3 5 8