How to propagate an exception in java

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無奈伤痛
無奈伤痛 2020-12-19 00:30

I am a C programmer and just learning some java recently because I am developing one android application. Currently I am in a situation. Following is the one.



        
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4条回答
  • 2020-12-19 01:03

    Don't catch it and rethrow again. Just do this and catch it in the place you want

    public void myMethod() throws ExceptionType1, ExceptionType2 {
        // other code
    }
    

    Example

    public void someMethod() {
        try {
            myMethod();
        } catch (ExceptionType1 ex) {
            // show your dialog
        } catch (ExceptionType2 ex) {
            // show your dialog
        }
    }
    
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  • 2020-12-19 01:15

    Just rethrow the exception

    throw Excp1;

    You will need to add the exception type to the MyMthod() declaration like this

    public void MyMethod() throws ExceptionType1, ExceptionType2  {
    
       try{
       //Some code here which can throw exceptions
       }
       catch(ExceptionType1 Excp1){
           throw Excp1;
       }
       catch(ExceptionType2 Excp2){
           throw Excp2;
       }
    }
    

    Or just omit the try at all since you are no longer handling the exceptions, unless you put some extra code in the catch statements doing things with the exception before rethrowing it.

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  • 2020-12-19 01:21

    I always do it like this :

    public void MyMethod() throws Exception
    {
        //code here
        if(something is wrong)
            throw new Exception("Something wrong");
    }
    

    then when you call the function

    try{
        MyMethod();
       }catch(Exception e){
        System.out.println(e.getMessage());
    }
    
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  • 2020-12-19 01:24

    Just don't catch the exception in the first place, and change your method declaration so that it can propagate them:

    public void myMethod() throws ExceptionType1, ExceptionType2 {
        // Some code here which can throw exceptions
    }
    

    If you need to take some action and then propagate, you can rethrow it:

    public void myMethod() throws ExceptionType1, ExceptionType2 {
        try {
            // Some code here which can throw exceptions
        } catch (ExceptionType1 e) {
            log(e);
            throw e;
        }
    }
    

    Here ExceptionType2 isn't caught at all - it'll just propagate up automatically. ExceptionType1 is caught, logged, and then rethrown.

    It's not a good idea to have catch blocks which just rethrow an exception - unless there's some subtle reason (e.g. to prevent a more general catch block from handling it) you should normally just remove the catch block instead.

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