How come string.maketrans does not work in Python 3.1?

Question

I\'m a Python newbie.

How come this doesn\'t work in Python 3.1?

from string import maketrans   # Required to call maketrans function.

intab = \"aei         


        

Answer 1

If you absolutely insist on working with 8-bit bytes:

>>> intab = b"aeiou"
>>> outtab = b"12345"
>>> trantab = bytes.maketrans(intab, outtab)
>>> strg = b"this is string example....wow!!!";
>>> print(strg.translate(trantab));
b'th3s 3s str3ng 2x1mpl2....w4w!!!'
>>>

Answer 2

Stop trying to learn Python 3 by reading Python 2 documentation.

intab = 'aeiou'
outtab = '12345'

s = 'this is string example....wow!!!'

print(s.translate({ord(x): y for (x, y) in zip(intab, outtab)}))

Answer 3

Here's my final Python (3.1) code posted here just for reference:

"this is string example....wow!!!".translate(bytes.maketrans(b"aeiou",b"12345"))

Short and sweet, love it.

Answer 4

Hey here is the simple one liner which worked perfectly for me

import string
a = "Learning Tranlate() Methods"
print (a.translate(bytes.maketrans(b"aeiou", b"12345")))*

OUTPUT :::: L21rn3ng Tr1nl1t2() M2th4ds

Answer 5

You don't need to use bytes.maketrans() when str would be simpler and eliminate the need for the 'b' prefix:

print("Swap vowels for numbers.".translate(str.maketrans('aeiou', '12345')))

Answer 6

"this is string example....wow!!!".translate(str.maketrans("aeiou","12345"))

This works, and no additional byte transformation. I don't know the reason why to use byte instead of str.