I have a weird problem with python passing a list as parameter to a function. Here is the code:
def foobar(depth, top, bottom, n=len(listTop)):
print dir
You pass in the result of top.append()
to your function. top.append()
returns None:
>>> [].append(0) is None
True
You need to call .append()
separately, then pass in just top
:
top.append(listTop[i])
bottom.append(listBottom[i])
foobar(depth+1, top, bottom)
Note that the n=len(listTop)
argument in the function is both redundant and only ever executed once, namely when you create the function. It won't be evaluated each time you call the function. You can omit it safely from the version you posted here in any case.
top.append(listTop[i])
works in place and returns None