Swift sort dictionary by value

Question

I have a dictionary, [String : Double] with the following data:

Museum1 : 8785.8971799638
Museum2 : 34420.9643422388
Museum3 : 826.467789130732
         


        

Answer 1

It is not clear what your expectations are. There is really no such thing as a sorted dictionary. Your code is basically correct except for a misplaced parenthesis. I tried this:

let d = ["Museum1":8785.8971799638,
"Museum2":34420.9643422388,
"Museum3":826.467789130732,
"Museum4":304120.342151219]

for (k,v) in (Array(d).sorted {$0.1 < $1.1}) {
    println("\(k):\(v)")
}

Result:

Museum3:826.467789130732
Museum1:8785.8971799638
Museum2:34420.9643422388
Museum4:304120.342151219

If you think that's wrong, you need to explain why.

Answer 2

In Swift 2.2, this works

for (k,v) in (Array(d).sort {$0.1 < $1.1}) {
    print("\(k):\(v)")
}

Swift 3, it also works:

for (k,v) in (Array(yourDictionary).sorted {$0.1 < $1.1}) {
    print("\(k):\(v)")
}

Answer 3

Simple solution for Swift 4 and above...

let dict = ["Museum1":8785.8971799638,
            "Museum2":34420.9643422388,
            "Museum3":826.467789130732,
            "Museum4":304120.342151219]

let dictSortByValue = dict.sorted(by: {$0.value < $1.value} )

for item in dictSortByValue {
   print("\(item.key) \(item.value) ")
}

// Museum3 826.467789130732 
// Museum1 8785.8971799638 
// Museum2 34420.9643422388 
// Museum4 304120.342151219 

Apparently you can sort a Dictionary in Swift 4--no need to transform into an Array.