Find TOP 10 latest record for each BUYER_ID for yesterday's date

Question

This is the below table

CREATE TABLE IF NOT EXISTS TestingTable1 
( 
BUYER_ID BIGINT,
ITEM_ID BIGINT, 
CREATED_TIME STRING
)

And this is th

Answer 1

select * 
from (select buyer_id,item_id,created_time,row_num() over (partition by buyer_id order by created_time DESC)) a 
where a.row_num<=10

Answer 2

I am late answering this and I am sure you must be knowing the use of row_number function with Hive. Just an addition as a reference to previously good discussion.

select * from
(select buyer_id,item_id,created_time, row_number() over(partition by buyer_id over
created_time asc) row_num from yourtable)tab
where tab.row_num<=5;

Answer 3

  SELECT FIRST 10 *
    FROM TestingTable1
   WHERE buyer_id = 34512201
ORDER BY created_time DESC;