Converting exponential to float

Question

This is my code, trying to convert the second field of the line from exponential into float.

outputrrd = processrrd.communicate()
(output, error) = outputrrd         


        

Answer 1

The float is correct, just use format to display it as you want, i.e.:

print(format(the_float, '.8f'))

Answer 2

The reason is the use of comma in 6,0865000000e-01. This won't work because float() is not locale-aware. See PEP 331 for details.

Try locale.atof(), or replace the comma with a dot.

Answer 3

I think it is useful to you:

def remove_exponent(value):
    """
       >>>(Decimal('5E+3'))
       Decimal('5000.00000000')
    """
    decimal_places = 8
    max_digits = 16

    if isinstance(value, decimal.Decimal):
        context = decimal.getcontext().copy()
        context.prec = max_digits
        return "{0:f}".format(value.quantize(decimal.Decimal(".1") ** decimal_places, context=context))
    else:
        return "%.*f" % (decimal_places, value)

Answer 4

This work for me, try it out.

def remove_exponent(value):
    decial = value.split('e')
    ret_val = format(((float(decial[0]))*(10**int(decial[1]))), '.8f')
    return ret_val

Answer 5

Simply by casting string into float:

new_val = float('9.81E7')

Answer 6

The easy way is replace! One simple example:

value=str('6,0865000000e-01')
value2=value.replace(',', '.')
float(value2)
0.60865000000000002