Java HashMap not finding key, but it should

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隐瞒了意图╮ 2020-12-18 08:17

I have a strange issue occuring in my application, I will quickly explain global architecture and then my problem in depth.

I use a service to populate a HashM

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  • 2020-12-18 08:24

    Is your DomainObject class immutable? Does it have properly implemented hashCode and equals methods?

    Note that you will get into trouble if your DomainObject class is not immutable and you change the state of the object while it is in the map in a way that would change the result of calling hashCode or equals.

    hashCode must be implemented in such a way that it returns the same value for two objects whenever equals returns true when comparing these objects. See the API documentation of java.lang.Object.hashCode() for detailed information.

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  • 2020-12-18 08:25

    [This basically expands on Jesper's answer but the details may help you]

    Since recreating the map using new HashMap(map) is able to find the element I am suspecting that the hashCode() of the DomainObject changed after adding it to the Map.

    For example if your DomainObject looks the following

    class DomainObject {
        public String name;
        long hashCode() { return name.hashCode(); }
        boolean equals(Object other) { /* compare name in the two */'
    }
    

    Then

       Map<DomainObject, Boolean> m = new HashMap<DomainObject, Boolean>();
       DomainObject do = new DomainObject(); 
       do.name = "ABC";
       m.put(do, true); // do goes in the map with hashCode of ABC
       do.name = "DEF";
       m.get(do); 
    

    The last statement above will return null. Because the do object you have inside the map is under the bucket of "ABC".hashCode(); there is nothing in the "DEF".hashCode() bucket.

    The hashCode of the Objects in map should not change once added to map. The best way to ensure it is that the fields on which hashCode depends must be immutable.

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  • 2020-12-18 08:39

    Here is your clue:

    hashcode() on both objects returns similar value

    For the objects to be considered equal, their hash codes shouldn't just be similar, they must be identical.

    If two objects have different hash codes, then as far as the container is concerned the objects are different. There's no need to even call equals().

    From the Javadoc:

    The general contract of hashCode is:

    • If two objects are equal according to the equals(Object) method, then calling the hashCode method on each of the two objects must produce the same integer result.

    If I were you, I'd take a close look at DomainObject.hashcode() and DomainObject.equals() to see what's causing the contract to be broken.

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  • 2020-12-18 08:41

    map.get(do) returning null could be easily explained by assuming that the Boolean value for that key might be null but map.containsKey(do) returning false would require do's hashCode to be different at the time of calling containsKey(do) to it's hashCode at the time of retrieving it from the keySet.

    To see what's happening, you could (temporarily) use a more verbose implementation of HashMap... Maybe something like this:

    public class VerboseHashMap<K, V> implements Map<K, V> {
    
        private transient final static Logger logger = Logger.getLogger(VerboseHashMap.class);
        private HashMap<K, V> internalMap = new HashMap<K, V>();
    
        public boolean containsKey(Object o) {
            logger.debug("Object HashCode: " + o.hashCode());
            logger.debug("Map contents:");
            for (Entry<K, V> entry : internalMap.entrySet()) {
                logger.debug(entry.getKey().hashCode() + " - " + entry.getValue().toString());
            }
            return internalMap.containsKey(o);
        }
    
        public V get(Object key) {
            logger.debug("Object HashCode: " + key.hashCode());
            logger.debug("Map contents:");
            for (Entry<K, V> entry : internalMap.entrySet()) {
                 logger.debug(entry.getKey().hashCode() + " - " + entry.getValue().toString());
            }
            return internalMap.get(key);
        }
    
    }
    

    You'd need to map all the other requirements of the Map interface to your internalMap as well.

    Note: This code is not intended for production, nor is it in any way performance oriented, nice or unsmelly....

    2nd note (after seeing your code): To use your domain-object as a key for your hashMap, you should only use the immutable parts of your object for hashCode and equals (in this case the id-value). Else lazy-loading further values would change the hashCode...

    In Response to your comment:

    public class Demo extends TestCase {
    
    public void testMap() {
    
        Map<DomainObject, String> map = new HashMap<DomainObject, String>();
        DomainObject sb = new DomainObject();
        map.put(sb, "Some value");
        System.out.println(map.containsKey(sb));
        sb.value = "Some Text";
        System.out.println(map.containsKey(sb));
    
    }
    
        private static class DomainObject {
    
            public String value = null;
    
            @Override
            public int hashCode() {
                final int prime = 31;
                int result = 1;
                result = prime * result + ((value == null) ? 0 : value.hashCode());
                return result;
            }
    
            @Override
            public boolean equals(Object obj) {
                if (this == obj)
                    return true;
                if (obj == null)
                    return false;
                if (getClass() != obj.getClass())
                    return false;
                DomainObject other = (DomainObject) obj;
                if (value == null) {
                    if (other.value != null)
                        return false;
                } else if (!value.equals(other.value))
                    return false;
                return true;
            }
    
        }
    
    }
    

    prints

    true 
    false
    

    The HashCode for the key is computed at the time of putting it into the map.

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