loss calculation over different batch sizes in keras

Question

I know that in theory, the loss of a network over a batch is just the sum of all the individual losses. This is reflected in the Keras code for calculating total loss. Relev

Answer 1

The code you have posted concerns multi-output models where each output may have its own loss and weights. Hence, the loss values of different output layers are summed together. However, The individual losses are averaged over the batch as you can see in the losses.py file. For example this is the code related to binary cross-entropy loss:

def binary_crossentropy(y_true, y_pred):
    return K.mean(K.binary_crossentropy(y_true, y_pred), axis=-1)

Update: Right after adding the second part of the this answer (i.e. loss functions), as the OP, I was baffled by the axis=-1 in the definition of loss function and I thought to myself that it must be axis=0 to indicate the average over the batch?! Then I realized that all the K.mean() used in the definition of loss function are there for the case of an output layer consisting of multiple units. So where is the loss averaged over the batch? I inspected the code to find the answer: to get the loss value for a specific loss function, a function is called taking the true and predicted labels as well as the sample weights and mask as its inputs:

weighted_loss = weighted_losses[i]
# ...
output_loss = weighted_loss(y_true, y_pred, sample_weight, mask)

what is this weighted_losses[i] function? As you may find, it is an element of list of (augmented) loss functions:

weighted_losses = [
    weighted_masked_objective(fn) for fn in loss_functions]

fn is actually one of the loss functions defined in losses.py file or it may be a user-defined custom loss function. And now what is this weighted_masked_objective function? It has been defined in training_utils.py file:

def weighted_masked_objective(fn):
    """Adds support for masking and sample-weighting to an objective function.
    It transforms an objective function `fn(y_true, y_pred)`
    into a sample-weighted, cost-masked objective function
    `fn(y_true, y_pred, weights, mask)`.
    # Arguments
        fn: The objective function to wrap,
            with signature `fn(y_true, y_pred)`.
    # Returns
        A function with signature `fn(y_true, y_pred, weights, mask)`.
    """
    if fn is None:
        return None

    def weighted(y_true, y_pred, weights, mask=None):
        """Wrapper function.
        # Arguments
            y_true: `y_true` argument of `fn`.
            y_pred: `y_pred` argument of `fn`.
            weights: Weights tensor.
            mask: Mask tensor.
        # Returns
            Scalar tensor.
        """
        # score_array has ndim >= 2
        score_array = fn(y_true, y_pred)
        if mask is not None:
            # Cast the mask to floatX to avoid float64 upcasting in Theano
            mask = K.cast(mask, K.floatx())
            # mask should have the same shape as score_array
            score_array *= mask
            #  the loss per batch should be proportional
            #  to the number of unmasked samples.
            score_array /= K.mean(mask)

        # apply sample weighting
        if weights is not None:
            # reduce score_array to same ndim as weight array
            ndim = K.ndim(score_array)
            weight_ndim = K.ndim(weights)
            score_array = K.mean(score_array,
                                 axis=list(range(weight_ndim, ndim)))
            score_array *= weights
            score_array /= K.mean(K.cast(K.not_equal(weights, 0), K.floatx()))
        return K.mean(score_array)
return weighted

As you can see, first the per sample loss is computed in the line score_array = fn(y_true, y_pred) and then at the end the average of the losses is returned, i.e. return K.mean(score_array). So that confirms that the reported losses are the average of per sample losses in each batch.

Note that K.mean(), in case of using Tensorflow as backend, calls the tf.reduce_mean() function. Now, when K.mean() is called without an axis argument (the default value of axis argument would be None), as it is called in weighted_masked_objective function, the corresponding call to tf.reduce_mean() computes the mean over all the axes and returns one single value. That's why no matter the shape of output layer and the loss function used, only one single loss value is used and reported by Keras (and it should be like this, because optimization algorithms need to minimize a scalar value, not a vector or tensor).

Answer 2

I would like to summarize the brilliant answers in this page.

1. Certainly a model need a scalar value to optimize(i.e. Gradient Decent).
2. This important value is calculated on batch level.(if you set batch size=1, it is stochastic gradient descent mode. so the gradient is calculated on that data point)
3. In loss function, group aggregation function such as k.mean(), is specially activited on problems such as multi-classification, where to get one datapoint loss, we need sum many scalars along many labels.

4. In the loss history printed by model.fit, the loss value printed is a running average on each batch. So the value we see is actually a estimated loss scaled for batch_size*per datapoint.

5. Be aware that even if we set batch size=1, the printed history may use a different batch interval for print. In my case:

   self.model.fit(x=np.array(single_day_piece),y=np.array(single_day_reward),batch_size=1)
   

The print is:

 1/24 [>.............................] - ETA: 0s - loss: 4.1276
 5/24 [=====>........................] - ETA: 0s - loss: -2.0592
 9/24 [==========>...................] - ETA: 0s - loss: -2.6107
13/24 [===============>..............] - ETA: 0s - loss: -0.4840
17/24 [====================>.........] - ETA: 0s - loss: -1.8741
21/24 [=========================>....] - ETA: 0s - loss: -2.4558
24/24 [==============================] - 0s 16ms/step - loss: -2.1474

In my problem, there is no way a single datapoint loss could reach scale of 4.xxx.So I guess model take sum loss of first 4 datapoints. However,the batch size for tain is not 4.