Are there any existing libraries to parse a string as an ipv4 or ipv6 address, or at least identify whether a string is an IP address (of either sort)?
For IPv4, you can use
socket.inet_aton(some_string)
If it throws an exception, some_string
is not a valid ip address
For IPv6, you can use:
socket.inet_pton(socket.AF_INET6, some_string)
Again, it throws an exception, if some_string
is not a valid address.
ipaddr -- Google's IP address manipulation package.
Note that a proposal to include a revised version of the package in the Python standard library has recently been accepted (see PEP 3144).
IPv4 + IPv6 solution relying only on standard library. Returns 4
or 6
or raises ValueError
.
try:
# Python 3.3+
import ipaddress
def ip_kind(addr):
return ipaddress.ip_address(addr).version
except ImportError:
# Fallback
import socket
def ip_kind(addr):
try:
socket.inet_aton(addr)
return 4
except socket.error: pass
try:
socket.inet_pton(socket.AF_INET6, addr)
return 6
except socket.error: pass
raise ValueError(addr)
Try
apt-get install python-ipaddr
or get the source code from here
Yes, there is ipaddr
module, that can you help to check if a string is a IPv4/IPv6 address, and to detect its version.
import ipaddr
import sys
try:
ip = ipaddr.IPAddress(sys.argv[1])
print '%s is a correct IP%s address.' % (ip, ip.version)
except ValueError:
print 'address/netmask is invalid: %s' % sys.argv[1]
except:
print 'Usage : %s ip' % sys.argv[0]
But this is not a standard module, so it is not always possible to use it.
You also try using the standard socket
module:
import socket
try:
socket.inet_aton(addr)
print "ipv4 address"
except socket.error:
print "not ipv4 address"
For IPv6 addresses you must use socket.inet_pton(socket.AF_INET6, address)
.
I also want to note, that inet_aton
will try to convert (and really convert it) addresses like 10
, 127
and so on, which do not look like IP addresses.
I prefer ip_interface because it handles situations both with and without prefix mask, for example, both "10.1.1.1/24" as well as simply "10.1.1.1". Needless to say, works for both v4 as well as v6
from ipaddress import ip_interface
ip_interface("10.1.1.1/24").ip
ip_interface("10.1.1.1/24").ip.version
ip_interface("10.1.1.1").ip
ip_interface("10.1.1.1").ip.version