I trying to print out a dictionary in Python:
Dictionary = {\"Forename\":\"Paul\",\"Surname\":\"Dinh\"}
for Key,Value in Dictionary.iteritems():
print Key,
'but dictionaries in Python are sorted by values' maybe I'm mistaken here but what game you that ideea? Dictionaries are not sorted by anything.
You would have two solutions, either keep a list of keys additional to the dictionary, or use a different data structure like an array or arrays.
You can use collections.OrderedDict. It's available in python2.7 and python3.2+.
I wonder if it is an ordered dict that you want:
>>> k = "one two three four five".strip().split()
>>> v = "a b c d e".strip().split()
>>> k
['one', 'two', 'three', 'four', 'five']
>>> v
['a', 'b', 'c', 'd', 'e']
>>> dx = dict(zip(k, v))
>>> dx
{'four': 'd', 'three': 'c', 'five': 'e', 'two': 'b', 'one': 'a'}
>>> for itm in dx:
print(itm)
four
three
five
two
one
>>> # instantiate this data structure from OrderedDict class in the Collections module
>>> from Collections import OrderedDict
>>> dx = OrderedDict(zip(k, v))
>>> for itm in dx:
print(itm)
one
two
three
four
five
A dictionary created using the OrderdDict preserves the original insertion order.
Put another way, such a dictionary iterates over the key/value pairs according to the order in which they were inserted.
So for instance, when you delete a key and then add the same key again, the iteration order is changes:
>>> del dx['two']
>>> for itm in dx:
print(itm)
one
three
four
five
>>> dx['two'] = 'b'
>>> for itm in dx:
print(itm)
one
three
four
five
two
This may meet your need better:
Dictionary = {"Forename":"Paul","Surname":"Dinh"}
KeyList = ["Forename", "Surname"]
for Key in KeyList:
print Key,"=",Dictionary[Key]
First of all dictionaries are not sorted at all nor by key, nor by value.
And basing on your description. You actualy need collections.OrderedDict module
from collections import OrderedDict
my_dict = OrderedDict([("Forename", "Paul"), ("Surname", "Dinh")])
for key, value in my_dict.iteritems():
print '%s = %s' % (key, value)
Note that you need to instantiate OrderedDict
from list of tuples not from another dict as dict instance will shuffle the order of items before OrderedDict will be instantiated.
You can use a list of tuples (or list of lists). Like this:
Arr= [("Forename","Paul"),("Surname","Dinh")]
for Key,Value in Arr:
print Key,"=",Value
Forename = Paul
Surname = Dinh
you can make a dictionary out of this with:
Dictionary=dict(Arr)
And the correctly sorted keys like this:
keys = [k for k,v in Arr]
Then do this:
for k in keys: print k,Dictionary[k]
but I agree with the comments on your question: Would it not be easy to sort the keys in the required order when looping instead?
EDIT: (thank you Rik Poggi), OrderedDict does this for you:
od=collections.OrderedDict(Arr)
for k in od: print k,od[k]