Looping through unknown number of array arguments

Question

I am trying to figure out how to loop through several array arguments passed. For example: [1,2,3,4,5],[3,4,5],[5,6,7] If I pass it to a function, how would I have a functi

Answer 1

function loopThroughArguments(){
    // It is always good to declare things at the top of a function, 
    // to quicken the lookup!
    var i = 0,
        len = arguments.length;

    // Notice that the for statement is missing the initialization.
    // The initialization is already defined, 
    // so no need to keep defining for each iteration.
    for( ; i < len; i += 1 ){

        // now you can perform operations on each argument,
        // including checking for the arguments type,
        // and even loop through arguments[i] if it's an array!
        // In this particular case, each argument is logged in the console.
        console.log( arguments[i] );
    }

};

Answer 2

You can use arguments for this:

for(var arg = 0; arg < arguments.length; ++ arg)
{
    var arr = arguments[arg];

    for(var i = 0; i < arr.length; ++ i)
    {
         var element = arr[i];

         /* ... */
    } 
}

Answer 3

Use the built in arguments keyword which will contain the length of how many arrays you have. Use that as a basis to loop through each array.

Answer 4

Use forEach, as below:

'use strict';

    function doSomething(p1, p2) {
        var args = Array.prototype.slice.call(arguments);
        args.forEach(function(element) {
            console.log(element);
        }, this);
    }

    doSomething(1);
    doSomething(1, 2);