Get all hrefs as an array in jQuery

Question

My code looks like this:

  
Link 1
  <         


        

Answer 1

Stumbled into this question and came up with a more reusable answer:

$.fn.collect = function(fn) {
    var values = [];

    if (typeof fn == 'string') {
        var prop = fn;
        fn = function() { return this.attr(prop); };
    }

    $(this).each(function() {
        var val = fn.call($(this));
        values.push(val);
    });
    return values;
};

var ids = $('#ulList li').collect('id');
var links = $('#ulList a').collect('href');

You can also pass a function into collect like so:

var widths = $('#ulList li').collect(function() {
    return this.width();
});

Answer 2

I came looking for a one-liner. Here's what I came up with:

var hs=[]; $('a').each(function(i,a){hs.push(a.href);}); hs;

Answer 3

If you like one liners and hate having to instantiate an empty array.

[]
  .slice
  .call($('#ulList a'))
  .map(el => el.getAttribute('href'))

Answer 4

Same code as provided by Grimace but in ES6

const allLinks = $('#ulList a').map((i,el) => $(el).attr('href')).get();
const allIds = $('#ulList li').map((i,el) => $(el).attr('id')).get();

Answer 5

This should work.

var ids = [],
    hrefs = []
;   
$('#ulList')
    .find('a[href]')  // only target <a>s which have a href attribute
        .each(function() {
            hrefs.push(this.href);
        })
    .end()
    .find('li[id]')   // only target <li>s which have an id attribute
        .each(function() {
            ids.push(this.id);
        })
;

// ids = ['id1', 'id2', 'id3']
// hrefs = ['http://link1', 'http://link2', 'http://link3']

Answer 6

var links = [], ids = [];
var $ul = $('#ulList');
var $lis = $ul.children('li');
var $as = $lis.children('a');

for(var count = $lis.length-1, i = count; i >= 0; i--){
    ids.push($lis[i].id);
    links.push($as[i].href);
}