Why does simple echo in subprocess not working

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名媛妹妹
名媛妹妹 2020-12-17 19:52

I\'m trying to perform simple echo operation using subprocess:

import subprocess
import shlex

cmd = \'echo $HOME\'
proc = subprocess.Popen(shlex.split(cmd),         


        
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  • 2020-12-17 20:10

    On Unix shell=True implies that 2nd and following arguments are for the shell itself, use a string to pass a command to the shell:

    import subprocess
    
    cmd = 'echo $HOME'
    proc = subprocess.Popen(cmd, shell=True, stdout=subprocess.PIPE)
    print proc.communicate()[0],
    

    You could also write it as:

    import subprocess
    
    cmd = 'echo $HOME'
    print subprocess.check_output(cmd, shell=True),
    

    From the subprocess' docs:

    On Unix with shell=True, the shell defaults to /bin/sh. If args is a string, the string specifies the command to execute through the shell. This means that the string must be formatted exactly as it would be when typed at the shell prompt. This includes, for example, quoting or backslash escaping filenames with spaces in them. If args is a sequence, the first item specifies the command string, and any additional items will be treated as additional arguments to the shell itself. That is to say, Popen does the equivalent of:

    Popen(['/bin/sh', '-c', args[0], args[1], ...])
    
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  • 2020-12-17 20:16

    You are confusing the two different invocations of Popen. Either of these will work:

    proc=subprocess.Popen(['/bin/echo', 'hello', 'world'], shell=False, stdout=subprocess.PIPE)
    

    or

    proc=subprocess.Popen('echo hello world', shell=True, stdout=subprocess.PIPE)
    

    When passing shell=True, the first argument is a string--the shell command line. When not using the shell, the first argument is a list. Both produce this:

    print proc.communicate()
    ('hello world\n', None)
    
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