dismiss the popup window by back button

Question

I want to Dismiss the popup window by clicking outside of the popup window or by the back button, but when click on the back button my application exit\'s, instead of exitin

Answer 1

You can override onBackPressed() callback in your code and check to see if your pop-up is already showing(then dismiss it), else you call super to get normal behavior.

Answer 2

Try this way: Implement onBackPressed() and add

if(popup!=null) {
    popup.dismiss();
    popup=null;
}

And set your PopWindow with below:

popup.setOutsideTouchable(true);

Answer 3

Maintain global reference for PopUpWindow and override onBackPressed()...

@Override
public void onBackPressed() {
    if (popupWindow != null && popupWindow.isShowing()) {
        popupWindow.dismiss();
    } else {
        super.onBackPressed();
    }
}

To dismiss by the same Button...

    ivmainmenu.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
            if(popupWindow != null && popupWindow.isShowing()) {
                popupWindow.dismiss();
                popupWindow = null;
            } else {
                // show pop up now
            }
        }
    });

Answer 4

Try this..

Use PopupWindow popupWindow as Global variable

use popup.setOutsideTouchable(true);

@Override
public void onBackPressed() {
    if (popupWindow != null) {
        if (popupWindow.isShowing()) {
            popupWindow.dismiss();
        }
    } else {
        finish();
    }
}

Answer 5

Replace

popupWindow.setOutsideTouchable(false);

with this

popupWindow.setOutsideTouchable(true);
popupWindow.setFocusable(true);

Answer 6

please write onBackPressed() and have following code

if(popup!=null){
   //dismiss the popup
   popup.dismiss();
   //make popup null again
   popup=null;
}