Can I use a URL as the source for imagecreatefromjpeg() without enabling fopen wrappers?

Question

I know it’s possible to use imagecreatefromjpeg(), imagecreatefrompng(), etc. with a URL as the ‘filename’ with fopen(), but I\'m unable to enable the wrappers due to securi

Answer 1

You could always download the image (e.g. with cURL) to a temporary file, and then load the image from that file.

Answer 2

You could even implement a cURL based stream wrapper for 'http' using stream_wrapper_register.

Answer 3

You can download the file using cURL then pipe the result into imagecreatefromstring.

Example:

    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, $imageurl); 
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); // good edit, thanks!
    curl_setopt($ch, CURLOPT_BINARYTRANSFER, 1); // also, this seems wise considering output is image.
    $data = curl_exec($ch);
    curl_close($ch);

    $image = imagecreatefromstring($data);