What is the time complexity of LinkedList.getLast() in Java?

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伪装坚强ぢ 2020-12-17 15:06

I have a private LinkedList in a Java class & will frequently need to retrieve the last element in the list. The lists need to scale, so I\'m trying to decide whether I

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  • 2020-12-17 15:42

    It is O(1) and you should not have to cache it. The getLast method simply returns header.previous.element, so there is no computation and no traversal of the list. A linked list slows down when you need to find elements in the middle it since it starts one end and moves one element at a time.

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  • 2020-12-17 15:44

    From the Java 6 source code:

    * @author  Josh Bloch
     * @version 1.67, 04/21/06
     * @see     List
     * @see     ArrayList
     * @see     Vector
     * @since 1.2
     * @param <E> the type of elements held in this collection
     */
    
    public class LinkedList<E>
        extends AbstractSequentialList<E>
        implements List<E>, Deque<E>, Cloneable, java.io.Serializable
    {
        private transient Entry<E> header = new Entry<E>(null, null, null);
        private transient int size = 0;
    
        /**
         * Constructs an empty list.
         */
        public LinkedList() {
            header.next = header.previous = header;
        }
    
    ...
    
        /**
         * Returns the first element in this list.
         *
         * @return the first element in this list
         * @throws NoSuchElementException if this list is empty
         */
        public E getFirst() {
        if (size==0)
            throw new NoSuchElementException();
    
        return header.next.element;
        }
    
        /**
         * Returns the last element in this list.
         *
         * @return the last element in this list
         * @throws NoSuchElementException if this list is empty
         */
        public E getLast()  {
        if (size==0)
            throw new NoSuchElementException();
    
        return header.previous.element;
        }
    
    ...
    
    }
    

    so that's O(1) for both getFirst() & getLast()

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  • 2020-12-17 15:47

    It is O(1) because the list is doubly-linked. It keeps references to both head and tail.

    From documentation:

    Operations that index into the list will traverse the list from the beginning or the end, whichever is closer to the specified index.

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  • 2020-12-17 16:04

    The implementation of LinkedList.getLast() leaves no doubts - it's an O(1) operation. However, I didn't find it documented anywhere.

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  • 2020-12-17 16:07

    From the LinkedList docs:

    All of the operations perform as could be expected for a doubly-linked list. Operations that index into the list will traverse the list from the beginning or the end, whichever is closer to the specified index.

    It should be O(1) since a doubly-linked list will have a reference to its own tail. (Even if it doesn't explicitly keep a reference to its tail, it will be O(1) to find its tail.)

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