Calendar: day/month names in specific locale

Question

I am playing with Python\'s calendar module that\'s in the standard library. Basically I need a list of all days of a month, like so:

>>> import cal         


        

Answer 1

Here's the month part of Lauritz's answer updated for Python 3:

from calendar import month_name, different_locale
def get_month_name(month_no, locale):
    with different_locale(locale):
        return month_name[month_no])

Answer 2

Ha! Found an easy way to get localized day/month names:

>>> import locale
>>> locale.setlocale(locale.LC_ALL, 'de_DE')
'de_DE'
>>> import calendar
>>> calendar.month_name[10]
'Oktober'
>>> calendar.day_name[1]
'Dienstag'

Answer 3

This is from the source code of the calendar module:

def formatmonthname(self, theyear, themonth, width, withyear=True):
    with TimeEncoding(self.locale) as encoding:
        s = month_name[themonth]
        if encoding is not None:
            s = s.decode(encoding)
        if withyear:
            s = "%s %r" % (s, theyear)
        return s.center(width)

TimeEncoding and month_name can be imported from the calendar module. This gives the following method:

from calendar import TimeEncoding, month_name

def get_month_name(month_no, locale):
    with TimeEncoding(locale) as encoding:
        s = month_name[month_no]
        if encoding is not None:
            s = s.decode(encoding)
        return s

print get_month_name(3, "nb_NO.UTF-8")

For me the decode step is not needed, simply printing month_name[3] in the TimeEncoding context prints "mars", which is norwegian for "march".

For weekdays there's a similar method using the day_name and day_abbr dicts:

from calendar import TimeEncoding, day_name, day_abbr

def get_day_name(day_no, locale, short=False):
    with TimeEncoding(locale) as encoding:
        if short:
            s = day_abbr[day_no]
        else:
            s = day_name[day_no]
        if encoding is not None:
            s = s.decode(encoding)
        return s