Terse way to intersperse element between all elements in JavaScript array?

Question

Say I have an array var arr = [1, 2, 3], and I want to separate each element by an element eg. var sep = \"&\", so the output is [1, \"&a

Answer 1

you can also use the following:

var arr =['a', 'b', 'c', 'd'];
arr.forEach(function(element, index, array){
    array.splice(2*index+1, 0, '&');
});
arr.pop();

Answer 2

Updated for objects not using join method:

for (var i=0;i<arr.length;i++;) {
    newarr.push(arr[i]);
    if(i>0) { 
      newarr.push('&'); 
     }    
}

newarr should be:

newarr = ['a','&','b','&','c','&','d']; 

Answer 3

const arr = [1, 2, 3];

function intersperse(items, separator) {
  const result = items.reduce(
    (res, el) => [...res, el, separator], []);
  result.pop();
  return result;
}

console.log(intersperse(arr, '&'));

Answer 4

Using reduce but without slice

var arr = ['a','b','c','d'];
var lastIndex = arr.length-1;
arr.reduce((res,x,index)=>{
   res.push(x);
   if(lastIndex !== index)
    res.push('&');
  return res;
},[]);

Answer 5

My take:

const _ = require('lodash');

_.mixin({
    intersperse(array, sep) {
        return _(array)
            .flatMap(x => [x, sep])
            .take(2 * array.length - 1)
            .value();
    },
});

// _.intersperse(["a", "b", "c"], "-")
// > ["a", "-", "b", "-", "c"]

Answer 6

Using a generator:

function *intersperse(a, delim) {
  let first = true;
  for (const x of a) {
    if (!first) yield delim;
    first = false;
    yield x;
  }
}

console.log([...intersperse(array, '&')]);

Thanks to @Bergi for pointing out the useful generalization that the input could be any iterable.

If you don't like using generators, then

[].concat(...a.map(e => ['&', e])).slice(1)