i am passing images file names via textarea to php script to find information about each image in mysql db .The problem is i am trying to output those image file names that
You want to use mysqli_num_rows
if(mysqli_num_rows($result)) {
// Do your while loop here
}
You can use mysqli_num_rows()
in mysqli
if(mysqli_num_rows($result) > 0){
while($row = mysqli_fetch_array($result))
{
$totalRows++;
echo "<tr>";
echo "<td>" . $row['ID'] ."(".$totalRows. ")</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['imgPURL'] . "</td>";
echo "<td>" . $row['imgUrl'] . "</td>";
echo "</tr>";
}
} else {
echo "<tr><td colspan='4'>Not Found Image:".$line.'</td></tr>';
}
Use mysqli_num_rows to compare the number of rows in the result set.