How to use Bash substitution in a variable declaration

Question

I try to declare a variable x with all chars from a..x. On the command line (bash), substitution of a..x works w/o any ticks.

Answer 1

You can also use set (but be sure to save positional parameters if you still need them):

set {a..x}
x="$@"

For arrays, brace expansion works directly:

disks=( {a..x} )