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Regex for validating only numbers and dots

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隐瞒了意图╮
隐瞒了意图╮ 2020-12-17 00:20

I want a java regex expression that accepts only the numbers and dots.

for example, 

             1.1.1 ----valid
             1.1   ----valid
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  • 梦如初夏
    2020-12-17 00:42

    I guess this is what you want:

    Pattern.compile("(([0-9](\\.[0-9]*))?){1,13}(\\.[0-9]*)?(\\.[0-9]*)?(\\.[0-9]*)?", Pattern.CASE_INSENSITIVE | Pattern.UNICODE_CASE | Pattern.DOTALL | Pattern.MULTILINE);

    Explanation: It accepts numbers separated by dots; it starts and ends with number; a number can have multiple digits; one number without dots is not accepted.

    The output like this--

    • 1.1
    • 1.12
    • 1.1.5
    • 1.15.1.4
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  • 夕颜
    2020-12-17 00:44 
    <!DOCTYPE html>
<html>
<body>

<p>RegEx to allow digits and dot</p>
Number: <input type="text" id="fname" onkeyup="myFunction()">

<script>
function myFunction() {
    var x = document.getElementById("fname");
    x.value = x.value.replace(/[^0-9\.]/g,"");
}
</script>

</body>
</html>
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  • 滥情空心
    2020-12-17 00:48

    So you want a regex that wants numbers and periods but starts and ends with a number?

    "[0-9][0-9.]*[0-9]"

    But this isn't going to match things like 1. which doesn't have any periods, but does start and end with a number.

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  • 醉话见心
    2020-12-17 00:50

    I guess this is what you want:

    ^\d+(\.\d+)*$

    Explanation: It accepts numbers separated by dots; it starts and ends with number; a number can have multiple digits; one number without dots is also accepted.

    Variant without multiple digits:

    ^\d(\.\d)*$

    Variants where at least one dot is required:

    ^\d+(\.\d+)+$
^\d(\.\d)+$

    Don't forget that in Java you have to escape the \ symbols, so the code will look like this:

    Pattern NUMBERS_WITH_DOTS = Pattern.compile("^\\d+(\\.\\d+)*$");
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  • 孤城傲影
    2020-12-17 01:03 
    "^\\d(\\.\\d)*$"

1     ----valid (if it must be not valid, replace `*` => `+` )
1.1.1 ----valid
1.1   ----valid
1.1.1.1---valid
1.    ----not valid
11.1.1 ---not valid (if it must be valid, add `+` after each `d`)
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